A Level Chemistry 9701 Paper 23, May/June 2024

Question paper and mark scheme60 marks5 questions

Solve it on ExamPal

Practise

Untimed. Write on the paper and check as you go.

Start

Exam

Timed, with a clock you set, like sitting the real paper.

Start

Opens full screen.

Papers open in

Opening the question paper

Read as textThe questions and the mark scheme as plain text. Easier to read on a phone.

Question paper

9701/23 · May/June 2024

Download PDF
1
a(i)

Explain the lack of reactivity of nitrogen gas, N2(g).

[2]
a(ii)

Covalent bonds can be σ bonds or π bonds. Complete Table 1.1 to show the number of σ and π bonds in a molecule of N2 and to describe how the orbitals overlap to form σ and π bonds. Table 1.1

σ bondπ bond
number of bonds in N2
how the orbitals overlap
[4]
b(i)

A sample of Al reacts with an excess of Cl2. State the oxidation number of Al in the product of the reaction. oxidation number of Al ................................................................................................

[1]
b(ii)

State what determines the maximum oxidation number of the Period 3 elements in their oxides.

[1]
c(i)

Separate samples of aluminium oxide, Al2O3, and phosphorus(V) oxide, P4O10, react with an excess of NaOH(aq) at room temperature. Give the state of Al2O3 and P4O10 at room temperature. Al2O3 ................................................................................................................................. P4O10 .................................................................................................................................

[1]
c(ii)

Write an equation for the reaction of each oxide with an excess of NaOH(aq) at room temperature. Al2O3+ ............................................................................................................................ P4O10+ ...........................................................................................................................

[2]
d(i)

The oxide of silicon reacts with calcium oxide in an addition reaction to produce calcium silicate, CaSiO3. The oxidation number of calcium in CaSiO3 is +II. Deduce the oxidation number of silicon in calcium silicate. oxidation number of silicon ..........................................................................................

[1]
d(ii)

Calcium oxide can be made from calcium carbonate in a single-step reaction. Identify the type of reaction that occurs.

[1]
2

N2(g) reacts with H2(g) in the Haber process, as shown in reaction 1. reaction 1 N2(g)+3H2(g)⇌2NH3(g)ΔH=−x kJ mol−1 Table 2.1 shows the different conditions used to produce three equilibrium mixtures, A, B and C. Table 2.1

ABC
initial molar ratio of N2:H2 added1:31:31:3
temperature/∘C5005001000
pressure/atm100010001000
iron present in mixturenoyesno
percentage yield of NH3(g) at equilibrium58xy
a

Describe and explain the change, if any, to the percentage yield of NH3(g) produced in B compared to A.

[1]
b(i)

Describe and explain the change, if any, to the percentage yield of NH3(g) produced in C compared to A.

[1]
b(ii)

Describe and explain the change to the rate of the forward reaction that occurs to establish the equilibrium in C compared to A. You do not need to refer to the Boltzmann distribution in your answer.

[2]
c(i)

Write an expression for the equilibrium constant, Kp, for reaction 1. State the units. Kp= units ..............................

[2]
c(ii)

Equilibrium mixture D is made when 1.0 mol of N2(g) and 3.0 mol of H2(g) are added to a sealed container at 750 ∘C and 1000 atm and left to reach equilibrium. This mixture contains 1.16 mol of NH3(g). Calculate the mole fraction of NH3(g) in D. mole fraction of NH3(g)= ..............................

[2]
c(iii)

The mole fraction of N2(g) is 0.625 in a new equilibrium mixture, E. Calculate the partial pressure of N2(g) in E when the total pressure is 1000 atm. partial pressure of N2(g)= .............................. atm

[1]
d(i)

When oxides of nitrogen escape into the atmosphere they may be involved in: • formation of acid rain from sulfur dioxide • formation of photochemical smog. Identify the role of NO and NO2 in the formation of H2SO4 from SO2 in the atmosphere to produce acid rain. Use relevant equations to support your answer.

[3]
d(ii)

Outline how NO and NO2 may contribute to the formation of photochemical smog.

[2]
3
a

Write an equation to show the reaction for the standard enthalpy change of formation of H2O. Include state symbols.

[2]
b

Water is one of the products in the reaction of B2O3 and NH3, as shown in reaction 2. reaction 2 B2O3+2NH3→2BN+3H2O Table 3.1 shows information about the standard enthalpy change of formation, ΔHf⊖, of some substances. Table 3.1

substanceΔHf⊖/kJ mol−1
B2O3−1264
NH3−46
BN−134
H2O−286

Calculate the enthalpy change, ΔH, for reaction 2 using the data from Table 3.1. ΔH= .............................. kJ mol−1

[2]
c(i)

Boron carbide is a hard crystalline solid that has a melting point greater than 2000 ∘C. Suggest the structure and bonding in boron carbide.

[1]
c(ii)

100 g of pure boron carbide contains 78.26 g of boron. Calculate the empirical formula of boron carbide. Show your working. empirical formula of boron carbide ..............................

[2]
4
Figure 1 of 2 for question 4
Figure 2 of 2 for question 4
a

NH3(g) reacts with HCl(g) to produce NH4Cl(s), as shown. NH3(g)+HCl(g)→NH4Cl(s) Draw a diagram to show the ionic, covalent and coordinate bonding present in a formula unit of NH4Cl.

[2]
b(i)

An exothermic reaction occurs when NH4+(aq) is added to OH−(aq). Identify the type of reaction.

[1]
b(ii)

Construct an ionic equation for the reaction of NH4+ and OH−.

[1]
c(i)

Substitution reactions of NH3 and OH− with halogenoalkanes both involve a lone pair of electrons. Name the role of NH3 and OH− in these reactions.

[1]
c(ii)

Suggest which species, NH3 or OH−, is more reactive during these reactions. Explain your answer.

[1]
d

When 2-bromo-2-methylpropane reacts with OH−, two mechanisms, SN1 and SN2, both occur. The SN2 mechanism has a slower rate. Fig. 4.1 shows the reaction pathway diagram for the SN1 mechanism. Sketch a graph on Fig. 4.1 to show the reaction pathway for the SN2 mechanism.

[2]
e(i)

Complete Fig. 4.2 to show the mechanism for the SN1 reaction that occurs when CH3CHBrC2H5 reacts with NH3 to produce CH3CH(NH2)C2H5. Include charges, dipoles, lone pairs of electrons and curly arrows, as appropriate.

[3]
e(ii)

Identify the inorganic product that forms in the reaction in Fig. 4.2.

[1]
e(iii)

Give the systematic name for the organic product CH3CH(NH2)C2H5.

[1]
f(i)

Complete Table 4.1 by drawing the structural formula of the intermediate that is formed when 2-bromo-2-methylpropane reacts in an SN1 reaction. Table 4.1

[1]
f(ii)

Identify the halogenoalkane in Table 4.1 that has the greater tendency to react using the SN1 mechanism. Explain your answer.

[2]
5
Figure 1 of 7 for question 5
Figure 2 of 7 for question 5
Figure 3 of 7 for question 5
Figure 4 of 7 for question 5
Figure 5 of 7 for question 5
Figure 6 of 7 for question 5
Figure 7 of 7 for question 5
a

M reacts to form R by the addition of one reagent, as shown in Fig. 5.1. Fig. 5.1 Identify the reagent and conditions for this reaction.

[1]
b(i)

R is also made from M by two steps, as shown in Fig. 5.2. Fig. 5.2 Identify the reagents and conditions for steps 1 and 2 in Fig. 5.2. step 1 ................................................................................................................................ step 2 ................................................................................................................................

[2]
b(ii)

Name the mechanism for step 1 in Fig. 5.2.

[1]
c

The infrared spectrum of R is shown in Fig. 5.3. Fig. 5.3 Table 5.1

bondfunctional groups containing the bondcharacteristic infrared absorption range (in wavenumbers)/cm−1
C−Ohydroxy, ester1040--1300
C=Caromatic compound, alkene1500--1680
C=Oamide1640--1690
carbonyl, carboxyl1670--1740
ester1710--1750
C≡Nnitrile2200--2250
C−Halkane2850--2950
N−Hamine, amide3300--3500
O−Hcarboxyl2500--3000
hydroxy3200--3650

Use the absorptions in the region above 1500 cm−1 in Table 5.1 when answering this question. • Add F to Fig. 5.3 to identify the peak that is present in an infrared spectrum of both Q and R. Identify the bond that corresponds to the absorption for F. ........................................................................................................................................... • Add G to Fig. 5.3 to identify the peak that is not present in an infrared spectrum of Q. Identify the bond that corresponds to the absorption for G. ...........................................................................................................................................

[2]
d(i)

Y is made from Q in a three-step reaction. Fig. 5.4 Draw the structure of W in the box in Fig. 5.4.

[1]
d(ii)

In step 2, W is heated with HCl(aq) to produce X and an inorganic product. Identify the formula of the inorganic product.

[1]
d(iii)

In step 3, X reacts with reducing agent Z to produce Y. Complete the equation for the reaction of X with Z. Use a molecular formula to represent the organic product. Use [H] to represent one atom of hydrogen from Z. ...... C8H12O4+ ......[H] → .........................................................................................

[1]
d(iv)

Identify Z.

[1]

Mark scheme

9701/23 · May/June 2024

Download PDF

1a(i) · 2 marks

  • M1

    (N2 molecules /molecule(s) of N2) have a strong triple (covalent) bond

  • M2

    (N2 molecules /molecule(s) of N2) are non-polar

1a(ii) · 4 marks

  • 1 mark

    no of bonds for σ bond: 1

  • 1 mark

    no of bonds for π bond: 2

  • 1 mark

    how orbitals overlap for σ bond: direct (orbital overlap)

  • 1 mark

    how orbitals overlap for π bond: sideways (overlap of adjacent p orbitals)

1b(i) · 1 mark

  • 1 mark

    (+)III

1b(ii) · 1 mark

  • 1 mark

    number of outer / valence electrons

1c(i) · 1 mark

  • 1 mark

    both states shown as solid

1c(ii) · 2 marks

  • M1

    correctly balanced equation for aluminium oxide Al2O3 + 2NaOH + 3H2O → 2NaAl(OH)4

  • M2

    correctly balanced equation for P4O10 and an excess of NaOH P4O10 + 12NaOH → 4Na3PO4 + 6H2O

1d(i) · 1 mark

  • 1 mark

    (+)IV

1d(ii) · 1 mark

  • 1 mark

    thermal decomposition

2a · 1 mark

  • 1 mark

    58% / no change / stays the same AND catalysts don’t affect yield / iron is a catalyst

2b(i) · 1 mark

  • 1 mark

    less yield (in C than A) AND (as) exothermic (forward reaction)

2b(ii) · 2 marks

  • M1

    more collisions with particles that have E > Ea AND increase frequency of effective collisions

  • M2

    (initial) rate (of the forward reaction) increases

2c(i) · 2 marks

  • M1

    Kp = (pNH3)2 / (pN2)(pH2)3

  • M2

    atm–2

2c(ii) · 2 marks

  • M1

    correct amount N2 at equilibrium = 1 – 1.16 / 2 = 0.42 AND correct amount H2 at equilibrium = 3.0 – (1.16 × 3 / 2) = 1.26

  • M2

    express amount of ammonia as a mol fraction in terms of total amount of N2+H2+NH3 at equilibrium = 1.16 / (N2 + H2 + 1.16) = 0.408 OR 0.41

2c(iii) · 1 mark

  • 1 mark

    0.625 × 1000 = 625 (atm)

2d(i) · 3 marks

  • M1

    catalyst

  • M2

    2 equations to show the catalytic activity of NO2 in formation of SO3 from SO2 - SO2 + NO2 → NO + SO3 - 2NO + O2 → 2NO2

  • M3

    describe production of H2SO4 from SO3 and water (can be shown in an equation). SO3 then reacts with (rain)water / moisture / water vapour to make sulfuric acid / H2SO4 OR SO3 + H2O → H2SO4

2d(ii) · 2 marks

  • M1

    unburned hydrocarbons combine with NO and / NO2

  • M2

    to form PAN / peroxyac(et)yl nitrate

3a · 2 marks

  • M1

    correct equation only: H2 + ½O2 → H2O

  • M2

    correct state symbols based on this equation: (g) + (g) → (l)

3b · 2 marks

  • M1

    correct expression in terms of all 4 enthalpy changes of formation AND correct stoichiometry (as described in given equation)

  • M2

    correct calculation based on figures given: ∆H = –(–1264) – (2 × –46) + (2 × –134) + (3 × –286) = (+)230 kJ mol–1

3c(i) · 1 mark

  • 1 mark

    giant (molecular and) covalent

3c(ii) · 2 marks

  • M1

    give correct expression or calculate mol B compared to mol C 78.26 / 10.8 (= 7.246 / 7.25 mol B) AND 21.74 / 12 (=1.81(2) mol C)

  • M2

    Find B : C ratio AND use this to state empirical formula 7.246 to 7.25 / 1.817 to 1.82 = 3.99 to 3.98 mol B : 1 mol C (so) B4C OR CB4

4a · 2 marks

  • M1

    (ionic bond between) NH4+ and Cl– AND 4 N—H covalent bonds OR 4 shared pairs of electrons in NH4

  • M2

    1 N—H coordinate bond OR arrow on bond/line in correct direction or only 1 bonding pair using the same symbol for electrons1

4b(i) · 1 mark

  • 1 mark

    acid–base reaction

4b(ii) · 1 mark

  • 1 mark

    NH4+ + OH– → NH3 + H2O

4c(i) · 1 mark

  • 1 mark

    nucleophile

4c(ii) · 1 mark

  • 1 mark

    OH– (more reactive because) negatively charged species more attracted to halogenoalkane and / or Cδ+ and / or intermediate and / or C+ OR NH3 (more reactive because) N electrons less tightly held OR N is more able to donate (lp) electrons (to make the covalent bond) OR N is less electronegative ORA

4d · 2 marks

  • M1

    same start energy and finishing energy AND single hump

  • M2

    transition state / activation energy shown in answer is higher than both transition state energies shown in reaction profile (as the reaction is slower)

4e(i) · 3 marks

  • M1

    dipole and correct arrow on C—Br of 2-bromobutane

  • M2

    lone pair on NH3 attacking C(+) of the intermediate drawn

  • M3

    curly arrow showing bond between N—H breaking and pointing towards the N

4e(ii) · 1 mark

  • 1 mark

    NH4Br / ammonium bromide

4e(iii) · 1 mark

  • 1 mark

    butan-2-amine OR butyl-2-amine

4f(i) · 1 mark

  • 1 mark

4f(ii) · 2 marks

  • M1

    2-bromo-2-methylpropane AND more stable carbocation / C+

  • M2

    alkyl groups have an inductive effect (of alkyl groups) AND 2-bromo-2-methylpropane has more / most alkyl groups attached (to C+) / carbocation contains more alkyl groups

5a · 1 mark

  • 1 mark

    cold dilute KMnO4 OR cold dilute potassium manganate(VII)

5b(i) · 2 marks

  • 1 mark

    step 1 …..Br2 (in the dark)

  • 1 mark

    step 2 …..NaOH(aq) + heat

5b(ii) · 1 mark

  • 1 mark

    electrophilic addition

5c · 2 marks

  • M1

    peak shown around 2850–2950 labelled F AND (corresponds to) C—H

  • M2

    peak shown around 3200–3600 labelled G AND (corresponds to) O—H (in hydroxy(l) / alcohol)

5d(i) · 1 mark

  • 1 mark

    W =

5d(ii) · 1 mark

  • 1 mark

    NH4Cl

5d(iii) · 1 mark

  • 1 mark

    C8H12O4 + 8[H] → C8H16O2 + 2H2O

5d(iv) · 1 mark

  • 1 mark

    LiAlH4

Questions

  1. 1
    Question 113 marks
    Mark scheme ›
  2. 2
    Question 214 marks
    Mark scheme ›
  3. 3
    Question 37 marks
    Mark scheme ›
  4. 4
    Question 416 marks
    Mark scheme ›
  5. 5
    Question 510 marks
    Mark scheme ›

More 9701 papers

Other papers from May/June 2024

Solve it on ExamPalStart