A Level Mathematics 9709 Paper 32, May/June 2023

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Question paper

9709/32 · May/June 2023

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1

Solve the inequality ∣5x−3∣<2∣3x−7∣.

[4]
2

Solve the equation ln⁡(2x2−3)=2ln⁡x−ln⁡2, giving your answer in an exact form.

[3]
3
a

On an Argand diagram, sketch the locus of points representing complex numbers z satisfying ∣z+3−2i∣=2.

[2]
b

Find the least value of ∣z∣ for points on this locus, giving your answer in an exact form.

[2]
4

Solve the equation 2cos⁡x−cos⁡12x=1 for 0⩽x⩽2π.

[5]
5

The complex number 2+yi is denoted by a, where y is a real number and y<0. It is given that f(a)=a3−a2−2a.

a

Find a simplified expression for f(a) in terms of y.

[3]
b

Given that Re(f(a))=−20, find arg⁡a.

[3]
6

The equation cot⁡12x=3x has one root in the interval 0<x<π, denoted by α.

a

Show by calculation that α lies between 0.5 and 1.

[2]
b

Show that, if a sequence of positive values given by the iterative formula xn+1=13(xn+4tan⁡−1(13xn)) converges, then it converges to α.

[2]
c

Use this iterative formula to calculate α correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[3]
7

The equation of a curve is 3x2+4xy+3y2=5.

a

Show that dydx=−3x+2y2x+3y.

[4]
b

Hence find the exact coordinates of the two points on the curve at which the tangent is parallel to y+2x=0.

[5]
8
a

The variables x and y satisfy the differential equation dydx=4+9y2e2x+1. It is given that y=0 when x=1. Solve the differential equation, obtaining an expression for y in terms of x.

[7]
b

State what happens to the value of y as x tends to infinity. Give your answer in an exact form.

[1]
9

Let f(x)=2x2+17x−17(1+2x)(2−x)2.

a

Express f(x) in partial fractions.

[5]
b

Hence show that ∫01f(x) dx=52−ln⁡72.

[5]
10

The diagram shows the curve y=(x+5)3−2x and its maximum point M.

Figure 1 of 1 for question 10
a

Find the exact coordinates of M.

[5]
b

Using the substitution u=3−2x, find by integration the area of the shaded region bounded by the curve and the x-axis. Give your answer in the form a13, where a is a rational number.

[5]
11

The points A and B have position vectors i+2j−2k and 2i−j+k respectively. The line l has equation r=i−j+3k+μ(2i−3j+4k).

a

Show that l does not intersect the line passing through A and B.

[5]
b

Find the position vector of the foot of the perpendicular from A to l.

[4]

Mark scheme

9709/32 · May/June 2023

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1 · 4 marks

  • B1

    State or imply non-modular inequality (5x−3)2<22(3x−7)2, or corresponding quadratic equation, or pair of linear equations (5x−3)=±2(3x−7)

  • M1

    Solve a 3-term quadratic, or solve two linear equations for x

  • A1

    Obtain critical values x=1711 and x=11

  • A1

    State final answer x<1711, x>11

2 · 3 marks

  • M1

    Use law of the logarithm of a power, quotient or product

  • A1

    Remove logarithms and obtain a correct equation in x

  • A1

    Obtain final answer x=2 only

3a · 2 marks

  • B1

    Show a circle with centre –3 + 2i.

  • 1 mark

    Show a circle with radius 2

3b · 2 marks

  • M1

    Carry out a correct method for finding the least value of ∣z∣

  • A1

    Obtain answer 13−2 or 17−413

4 · 5 marks

  • 1 mark

    Use correct double angle formula to obtain an equation in cos⁡(x2) only

  • A1

    Obtain a 3 term quadratic in cos⁡(x2),

  • A1

    Obtain cos⁡(x2)=−34 and cos⁡(x2)=1

  • 1 mark

    Solve for the original x

  • A1

    Obtain x=0 and 4.84 and no others in the interval

5a · 3 marks

  • M1

    Substitute 2+yi in a3−a2−2a and attempt expansions of a2 and a3

  • M1

    Use i2=−1

  • A1

    Obtain final answer −5y2+(6y−y3)i

5b · 3 marks

  • M1

    Equate *their* −5y2 to −20 and solve for y

  • A1

    Obtain y=−2

  • A1

    Obtain final answer arg⁡a=−π4

6a · 2 marks

  • M1

    Calculate the values of a relevant expression or pair of expressions at x=0.5 and x=1

  • A1

    Complete the argument correctly with conclusion about change of sign or change of inequalities and with correct calculated values. Can all be in symbols – an explanation in words is not required.

6b · 2 marks

  • M1

    State x=13(x+4tan⁡−113x)

  • A1

    Rearrange to the given equation cot⁡(x2)=3x Need intermediate step between x2=tan⁡−113x and cot⁡(x2)=3x

6c · 3 marks

  • M1

    Use the iterative process correctly at least once

  • A1

    Obtain final answer 0.79

  • A1

    Show sufficient iterations to at least 4 d.p. to justify 0.79 to 2 d.p. or show there is a sign change in the interval (0.785, 0.795)

7a · 4 marks

  • B1

    State or imply 6ydydx as the derivative of 3y2

  • B1

    State or imply 4xdydx+4y as the derivative of 4xy

  • M1

    Equate derivative of LHS to zero and solve for dydx

  • A1

    Obtain dydx=−3x+2y2x+3y

7b · 5 marks

  • 1 mark

    Equate dydx to –2 and solve for x in terms of y or for y in terms of x

  • A1

    Obtain x=−4y or y=−x4

  • 1 mark

    Substitute *their* x=−4y or *their* y=−x4 in curve equation

  • A1

    Obtain y=±17 or x=±47

  • A1

    Obtain both pairs of values

8a · 7 marks

  • B1

    Separate variables correctly

  • B1

    Obtain term −12e−2x−1

  • M1

    Obtain term of the form atan⁡−1(3y2)

  • A1

    Obtain term 16tan⁡−1(3y2)

  • M1

    Use x=1, y=0 to evaluate a constant or as limits in a solution containing or derived from terms of the form atan⁡−1(by) and ce±(2x+1)

  • A1

    Obtain correct answer in any form

  • A1

    Obtain final answer y=23tan⁡(3e−3−3e−2x−1)

8b · 1 mark

  • 1 mark

    State that y approaches 23tan⁡(3e−3)

9a · 5 marks

  • B1

    State or imply the form A1+2x+B2−x+C(2−x)2

  • M1

    Use a correct method for finding a coefficient

  • A1

    Obtain one of A=−4, B=−3 and C=5

  • A1

    Obtain a second value

  • A1

    Obtain the third value

9b · 5 marks

  • 1 mark

    Integrate and obtain term −2ln⁡(1+2x)

  • 1 mark

    Integrate and obtain term 3ln⁡(2−x)

  • 1 mark

    Integrate and obtain term 52−x

  • M1

    Substitute limits correctly in an integral with two terms (obtained correctly) of the form aln⁡(1+2x)+bln⁡(2−x)+c2−x, where abc≠0

  • A1

    Obtain answer 52−ln⁡72 after full and correct working

10a · 5 marks

  • 1 mark

    Use the product rule correctly to obtain p(x+5)(3−2x)n+q(3−2x)12

  • A1

    Obtain correct derivative in any form

  • 1 mark

    Equate derivative to zero and obtain a linear equation

  • A1

    Obtain a correct linear equation.

  • A1

    Obtain answer (−23,13399)

10b · 5 marks

  • 1 mark

    Use the given substitution and reach a∫(132−u2)u12du

  • A1

    Obtain correct integral −12∫(132−u2)u12du

  • B1

    x=−5 and 32

  • 1 mark

    Use correct limits the right way round in an integral of the form a(263u32−25u52)

  • A1

    Obtain answer 1691513 or a=16915

11a · 5 marks

  • M1

    Carry out correct method for finding a vector equation for AB

  • A1

    Obtain [r=]i+2j−2k+λ(i−3j+3k)

  • M1

    Equate two pairs of components of general points on their AB and l and evaluate λ or μ

  • A1

    Obtain correct answer for λ or μ, e.g. λ=−1, μ=−2

  • A1

    Verify that all three equations are not satisfied and the lines fail to intersect (≠ is sufficient justification e.g. 0≠−3).

11b · 4 marks

  • B1

    Find AP⃗ for a general point P on l, e.g. −3j+5k+μ(2i−3j+4k)

  • M1

    Calculate scalar product of *their* AP⃗ and a direction vector for l and equate the result to zero

  • A1

    Obtain μ=−1

  • A1

    Obtain answer −i+2j−k

Questions

  1. 1
    Question 14 marks
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  2. 2
    Question 23 marks
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  3. 3
    Question 34 marks
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  4. 4
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  5. 5
    Question 56 marks
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  6. 6
    Question 67 marks
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  7. 7
    Question 79 marks
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  8. 8
    Question 88 marks
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  9. 9
    Question 910 marks
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  10. 10
    Question 1010 marks
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  11. 11
    Question 119 marks
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