O Level Mathematics 4024 Paper 22, May/June 2023

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4024/22 · May/June 2023

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1
a(i)

A shop buys some fruit. The table shows the bill for this fruit.

ItemQuantity (kg)Price per kg ($)Cost price ($)
Bananas500.5125.50
Oranges721.35p
Avocadosr1.95q
Pears45s51.30
Total cost price240.30

Find the value of each of p, q, r and s.

[4]
a(ii)

The shop sells all this fruit for a total of $325. Calculate the percentage profit.

[2]
b(i)(a)

In 2022, the shop's total sales were $34974. A pie chart is drawn to show the item types that make up these total sales. The sales for fruit were $9520.70. Calculate the angle representing fruit on the pie chart.

[2]
b(i)(b)

The angle representing frozen food is 46∘. Calculate the sales for frozen food.

[2]
b(ii)

The shop's total sales of $34974 in 2022 were a 4.4 increase on the total sales in 2021. Calculate the total sales in 2021.

[2]
2
a

One chocolate bar costs p cents and one packet of sweets costs 75 cents. Tanish pays $9.10 for 5 chocolate bars and 8 packets of sweets. Form an equation and solve it to find the value of p. Show your working.

[3]
b

Factorise 6ac−27c.

[2]
c

Write 3m2n10×5n9m as a single fraction in its simplest form.

[2]
d

Rearrange the formula y=3x25 to make x the subject.

[2]
e

A group of k numbers has a mean of 56.8. The number 52 is added to the group. The new mean is 56.5. Find the value of k.

[4]
3
Figure 1 of 2 for question 3
Figure 2 of 2 for question 3
a(i)

The diagram shows the equilateral triangle B and part of the regular polygon A which have a common side. The interior angle of polygon A is 165∘. Find the value of y.

[1]
a(ii)

Calculate the number of sides of polygon A.

[2]
b(i)

A, B and C are points on the circumference of a circle, centre O. Angle ABC=x∘. Show that angle OAC=(90−x)∘. Give reasons for your answer.

[3]
b(ii)

Angle BAO=54∘ and angle OCB=11∘. Find the value of x.

[2]
4
a

Complete the table of values for y=2x5.

x−101234
y0.10.20.40.81.6
[1]
b

Draw the graph of y=2x5 for −1⩽x⩽4.

[3]
c

By drawing a suitable line on the grid, solve 2x=6.

[2]
d(i)

Complete the table of values for 4y=2x+1.

x−124
y2.25
[1]
d(ii)

On the grid on page 8, draw the graph of 4y=2x+1 for −1⩽x⩽4.

[1]
d(iii)

Find the x-coordinates of the points where the line 4y=2x+1 crosses the graph of y=2x5.

[1]
d(iv)

The x-coordinates in part (d)(iii) are the solutions of the equation A×2x+Bx+C=0, where A, B and C are all integers. Use the equations 4y=2x+1 and y=2x5 to find the exact value of each of A, B and C.

[3]
5
a(i)

The table shows the population and area of three countries in 2019.

CountryPopulationArea (km2)
Sri Lanka2.18×1076.56×104
South Korea5.17×1071.00×105
Pakistan2.17×1088.82×105

Write down the value of the smallest population.

[1]
a(ii)

Find the difference in area between Sri Lanka and Pakistan. Give your answer in standard form.

[1]
a(iii)

The population density of a country is the number of people per square kilometre. Find the value of the largest population density from these countries.

[2]
b(i)

In standard form, A=8.6×10n and B=1.5×10n−1. Giving your answer in standard form, find in terms of n A−B

[1]
b(ii)

Giving your answer in standard form, find in terms of n A×B.

[2]
6

Sophia takes part in the Trio Challenge. She walks, then cycles and then swims. Trio Challenge Walk 6.3 km Cycle 3000 m Swim 1800 m

a

Write these distances walk:cycle:swim as a ratio in its simplest form.

[2]
b

Sophia walks at an average speed of 1.4 m/s. She completes the walk at 11 05. Find the time she starts walking.

[3]
c

Sophia cycles a distance of 3000 m correct to the nearest 10 metres. She cycles this distance in a time of 450 seconds correct to the nearest 10 seconds. Calculate the upper bound for her average cycling speed in metres per second.

[3]
7
a(i)

On Monday, the amount of money spent on a website by each customer was recorded. The table shows the results.

Amount of money ($m)0<m⩽3030<m⩽4040<m⩽5050<m⩽6060<m⩽90
Frequencyp18241924

The histogram shows some of the results. Find the value of p.

[1]
a(ii)

Complete the histogram.

[3]
a(iii)

One of these customers is selected at random to receive a discount voucher. Calculate the probability that this customer spent more than $50 on Monday.

[1]
b(i)

The table shows the amount of money spent on a website by each customer on Tuesday.

Amount of money ($m)0<m⩽3030<m⩽4040<m⩽5050<m⩽6060<m⩽90
Frequency2216241914

Calculate an estimate of the mean.

[3]
b(ii)

An error was made and one of the sales on Tuesday was not included in the table. That customer spent $41. Tristan says: If that value had been included in the table, then the estimated mean would have been higher. Without calculation, explain why he is correct.

[1]
8
Figure 1 of 2 for question 8
Figure 2 of 2 for question 8
a(i)

The length of the rectangle R is twice its width. Rectangle R has a perimeter of 20.4 cm. Find the length and width of the rectangle R.

[2]
a(ii)

Rectangle S is mathematically similar to rectangle R. Rectangle S has a perimeter of 30.6 cm. Calculate the length of rectangle S.

[2]
b(i)

A piece of card is a sector of a circle with sector angle 75∘ and radius 8 cm. Find an expression, in terms of π, for the arc length of the sector. Give your answer in its simplest form.

[2]
b(ii)

[Volume of a cone =13πr2h] The piece of card forms the curved surface area of a cone. The cone is filled to the top with water. Calculate the volume of water in the cone.

[5]
9

A, B and C are points on horizontal ground. The bearing of B from A is 072∘. The bearing of C from A is 205∘. AB=170 m and AC=95 m.

Figure 1 of 2 for question 9
Figure 2 of 2 for question 9
a

Calculate BC.

[4]
b

Find the bearing of A from C.

[2]
c(i)

The point D lies on the horizontal ground, due south of A and due east of C. Show that AD=86.1 m, correct to 1 decimal place.

[2]
c(ii)

A point X is at the top of a vertical mast at A. The angle of elevation of X from B is 7∘. Calculate the angle of elevation of X from D.

[4]
10
Figure 1 of 1 for question 10
a

F is the point (6,1), G is the point (−2,4) and GH⃗=(−1−8). Calculate ∣FH⃗∣.

[3]
b(i)

OA⃗=a, OB⃗=b and AC⃗=kb. X is the point on OC such that OX⃗=mOC⃗. Write OX⃗ in terms of m, k, a and b.

[2]
b(ii)

BX⃗=35a−12b Find the value of k.

[3]

Mark scheme

4024/22 · May/June 2023

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1a(i) · 4 marks

  • B1

    p = 97.2[0]

  • B1

    q = 66.3[0]

  • B1

    r = 34

  • B1

    s = 1.14

1a(ii) · 2 marks

  • 2 marks

    35.2 or 35.24 to 35.25

1b(i)(a) · 2 marks

  • 2 marks

    98

1b(i)(b) · 2 marks

  • 2 marks

    4468.9[0]

1b(ii) · 2 marks

  • 2 marks

    33 500

2a · 3 marks

  • B1

    5p + 8×75 = 910 or 5p = 910 – 8×75 or 5p100+8×75100=9.1[0] or 5p100=9.1[0]−8×75100

  • B2

    62

2b · 2 marks

  • 2 marks

    3c(2a – 9) or –3c(9 –2a) final answer

2c · 2 marks

  • 2 marks

    mn26 final answer

2d · 2 marks

  • 2 marks

    [±]5y3 or [±](5y3)12 oe final answer

2e · 4 marks

  • 4 marks

    15

3a(i) · 1 mark

  • 1 mark

    135

3a(ii) · 2 marks

  • 2 marks

    24

3b(i) · 3 marks

  • 3 marks

    Angle AOC = 2x angle at centre is twice angle at circumference Angle OAC = 180−2x2=90−x isosceles triangle

3b(ii) · 2 marks

  • 2 marks

    43

4a · 1 mark

  • 1 mark

    3.2 oe

4b · 3 marks

  • 3 marks

    Correct smooth curve

4c · 2 marks

  • B1

    Ruled line y = 1.2

  • B1

    2.5 to 2.7

4d(i) · 1 mark

  • 1 mark

    –0.25, 1.25 oe

4d(ii) · 1 mark

  • 1 mark

    Ruled line from (–1, –0.25) to (4, 2.25)

4d(iii) · 1 mark

  • 1 mark

    x-coordinates where ruled line 4y = 2x + 1 crosses y = 2x5

4d(iv) · 3 marks

  • M1

    2x5=2x+14 oe seen

  • A2

    A = 4, B = –10, C = –5 OR A = –4, B = 10, C = 5

5a(i) · 1 mark

  • 1 mark

    2.18 × 10⁷ or 21 800 000

5a(ii) · 1 mark

  • 1 mark

    8.16 × 10⁵ or 8.164 × 10⁵ cao

5a(iii) · 2 marks

  • 2 marks

    517 or 5.17 × 10² cao

5b(i) · 1 mark

  • 1 mark

    8.45 × 10ⁿ final answer

5b(ii) · 2 marks

  • 2 marks

    1.29 × 10²ⁿ final answer

6a · 2 marks

  • 2 marks

    21 : 10 : 6 final answer

6b · 3 marks

  • 3 marks

    [0]9 50[am]

6c · 3 marks

  • 3 marks

    6.75 nfww or 6.752 to 6.753 or 66789

7a(i) · 1 mark

  • 1 mark

    15

7a(ii) · 3 marks

  • 3 marks

    Completed histogram

7a(iii) · 1 mark

  • 1 mark

    43100 or 0.43 or 43%

7b(i) · 3 marks

  • 3 marks

    42.8[0] or 42.78 to 42.79

7b(ii) · 1 mark

  • 1 mark

    41 is in 40 < m ⩽ 50 so mid-value of 45 would have been used to estimate the mean which is higher than the estimated mean oe

8a(i) · 2 marks

  • 2 marks

    length = 6.8 width = 3.4

8a(ii) · 2 marks

  • 2 marks

    10.2 nfww

8b(i) · 2 marks

  • 2 marks

    10π3 or 103π or 313π final answer

8b(ii) · 5 marks

  • 5 marks

    22.7 to 22.9

9a · 4 marks

  • 4 marks

    245 nfww or 244.8 to 244.9

9b · 2 marks

  • 2 marks

    [0]25

9c(i) · 2 marks

  • M1

    cos⁡(their 25)=AD95 or sin⁡(90−their 25)=AD95 oe

  • A1

    86.09[9…] or 86.10

9c(ii) · 4 marks

  • 4 marks

    13.6 or 13.62 to 13.63 nfww

10a · 3 marks

  • 3 marks

    10.3 or 10.29 to 10.30

10b(i) · 2 marks

  • 2 marks

    m (a + kb) or ma + mkb oe

10b(ii) · 3 marks

  • 3 marks

    56

Questions

  1. 1
    Question 112 marks
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  2. 2
    Question 213 marks
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  3. 3
    Question 38 marks
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  4. 4
    Question 412 marks
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  5. 5
    Question 57 marks
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  6. 6
    Question 68 marks
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  7. 7
    Question 79 marks
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  8. 8
    Question 811 marks
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  9. 9
    Question 912 marks
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  10. 10
    Question 108 marks
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