O Level Mathematics 4024 Paper 21, Oct/Nov 2024

Question paper and mark scheme100 marks11 questions

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4024/21 · Oct/Nov 2024

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1

Basma owns a toy shop.

a

The sign shows the opening hours for the shop. Saturday to Wednesday 1030 to 1800 Thursday and Friday 1000 to 1930 Work out the length of time the shop is open in one week.

[1]
b

Basma employs 5 sales assistants and 2 supervisors. On one particular week, the 5 sales assistants each work for 30 hours and the 2 supervisors each work for 38 hours. For that week, the total amount Basma pays these 7 employees is $3324.70 . Basma pays each sales assistant $13.45 per hour. Calculate the amount Basma pays each supervisor per hour.

[3]
c

The exchange rate between dollars ($) and pounds (£) is $1 = £0.77 . Basma buys 50 identical games for a total of £245. She makes a profit of 39% when she sells each game. Calculate the selling price of one game in dollars. Give your answer correct to the nearest cent.

[4]
d

Basma invests $12000 in an account paying compound interest at a rate of 1.5% per year. At the end of year 1, she invests another $12000 in the same account. At the end of year 4, she takes $20000 out of the account. Calculate the amount of money remaining in the account at the end of year 4. Give your answer correct to the nearest cent.

[3]
2

In a traffic survey, information about the vehicles passing a checkpoint is recorded.

Figure 1 of 2 for question 2
Figure 2 of 2 for question 2
a(i)

160 vehicles pass the checkpoint in the morning. The table shows the number of people in each of these vehicles.

Number of peopleFrequencyPie chart angle
172
248
3 or more4090∘

Complete the table.

[2]
a(ii)

Complete the pie chart to show the results.

[1]
b(i)

The histogram shows the speeds of vehicles passing the checkpoint in the afternoon. Sanjay says the histogram shows that the range of the speeds is 50 km/h. Explain why he may not be correct.

[1]
b(ii)

Complete the frequency table.

Speed (s km/h)20<s⩽3030<s⩽4040<s⩽4545<s⩽5050<s⩽70
Frequency24
[3]
3
a

Complete the table for y=4+2x−x22.

x−2−10123456
y1.545.565.541.5
[2]
b

Draw the graph of y=4+2x−x22 for −2⩽x⩽6.

[3]
c

Find the equation of the line of symmetry of the graph of y=4+2x−x22.

[1]
d

On the grid, draw the line 3y=x+6 for −2⩽x⩽6.

[2]
e

Write down the x-coordinates of the points of intersection of the graphs of y=4+2x−x22 and 3y=x+6.

[1]
4

E={x:x is an integer 1⩽x⩽15} A={x:x is a multiple of 3} B={x:x is a factor of 30}

Figure 1 of 1 for question 4
a

Write down the elements of A.

[1]
b

Complete the Venn diagram.

[2]
c

x∈(A∪B)′ Find the smallest value of x.

[1]
d

Find n(A∩B′).

[1]
5
a(i)

Solve. y4=8

[1]
a(ii)

Solve. 3−4x=2x+12

[2]
b(i)

w=5x−6y Find the value of w when x=6.2 and y=−1.8.

[2]
b(ii)

Rearrange the formula to make x the subject.

[2]
c

Factorise. 15y−x2−3xy+5x

[2]
d

Write as a single fraction in its simplest form. 2x−3−4x+3+1

[4]
6
Figure 1 of 2 for question 6
Figure 2 of 2 for question 6
a

[Volume of sphere =43πr3] The diagram shows a sphere inside a cube. The sphere touches all 6 faces of the cube. The volume of the cube is 343 cm3. Calculate the volume of the sphere.

[3]
b

Solid A is mathematically similar to solid B. The volume of solid A is 540 cm3 and its height is 15 cm. The volume of solid B is 1280 cm3. Calculate the height of solid B.

[2]
c

[Curved surface area of a cone =πrl] The diagram shows a solid formed by joining a cone to a cylinder. The cone and the cylinder each have radius 6.3 cm. The slant height of the cone is 8.7 cm. The ratio height of cone:height of cylinder=2:3. Calculate the total surface area of the solid.

[5]
7

ABCD is a parallelogram with sides AB, BC, CD and DA. A is the point (−3,7) and B is the point (2,5). AD⃗=(−1−6)

a

Find the coordinates of point D.

[1]
b

Find ∣AD⃗∣.

[2]
c

Find AC⃗.

[3]
d

Line L is the line perpendicular to AB that passes through point D. Find the equation of line L.

[4]
8

ABCD is a field. AB=320 m, BC=250 m, CD=132 m and AD=365 m. Angle BCD=90∘.

Figure 1 of 1 for question 8
a

Ray walks from A to B at an average speed of 1.6 m/s. He then runs from B to C at an average speed of 2.8 m/s. Calculate Ray’s average speed from A to B to C.

[3]
b

The bearing of D from A is 243∘. Calculate the bearing of B from A.

[5]
9
Figure 1 of 2 for question 9
Figure 2 of 2 for question 9
a

ABD is a triangle. C is a point on BD and E is a point on AD. AB is parallel to EC and CD=DE. Find the value of x and the value of y.

[4]
b

PQR is a triangle. P and R are points on a circle, centre O. O is a point on PQ. QR is a tangent to the circle at R. QR=12 cm and angle RPQ=35∘. Calculate the area of triangle PQR.

[6]
10

Bag A contains red balls and green balls. The total number of balls in the bag is x. The number of green balls in the bag is 6 more than the number of red balls.

a

Show that the fraction of the balls in bag A that are red is x−62x.

[2]
b

Bag B also contains red balls and green balls. The number of red balls in bag B is x. The number of green balls in bag B is 4 times the number of green balls in bag A. Show that the fraction of the balls in bag B that are red is x3x+12.

[2]
c

x−62x=x3x+12 Show that x2−6x−72=0.

[3]
d

Solve by factorisation x2−6x−72=0.

[2]
e

x is the total number of balls in bag A. Use your answer to part (d) to find the number of green balls in bag A.

[1]
11

Mia has 25 shapes. She uses their properties to sort them into groups. The table shows the number of shapes in each group.

TriangleQuadrilateral
Line symmetry49
No line symmetry57
a

Mia takes one of the triangles at random, notes its properties and replaces it. Find the probability that it has line symmetry.

[2]
b

Mia takes one of the 25 shapes at random, notes its properties and replaces it. She then takes a second shape at random, notes its properties and replaces it. Find the probability that both shapes are quadrilaterals.

[2]
c

Mia takes three of the 25 shapes at random without replacement. Find the probability that only one of the shapes is a triangle with line symmetry.

[3]

Mark scheme

4024/21 · Oct/Nov 2024

Download PDF

1a · 1 mark

  • 1 mark

    56.5 oe

1b · 3 marks

  • 3 marks

    17.2[0] cao

1c · 4 marks

  • 4 marks

    8.85 final answer

1d · 3 marks

  • 3 marks

    5284.50

2a(i) · 2 marks

  • 2 marks

    162 108

2a(ii) · 1 mark

  • 1 mark

    Correct pie chart

2b(i) · 1 mark

  • 1 mark

    Data grouped so individual speeds not known oe

2b(ii) · 3 marks

  • 3 marks

    46 44 38 28

3a · 2 marks

  • 2 marks

    –2 –2

3b · 3 marks

  • 3 marks

    Correct smooth curve

3c · 1 mark

  • 1 mark

    x = 2

3d · 2 marks

  • 2 marks

    Correct ruled line

3e · 1 mark

  • 1 mark

    STRICT FT x-coordinates of intersection of their ruled line and their curve

4a · 1 mark

  • 1 mark

    3, 6, 9, 12, 15

4b · 2 marks

  • 2 marks

    Correct Venn diagram

4c · 1 mark

  • 1 mark

    4

4d · 1 mark

  • 1 mark

    2

5a(i) · 1 mark

  • 1 mark

    32

5a(ii) · 2 marks

  • 2 marks

    −32 oe final answer

5b(i) · 2 marks

  • 2 marks

    41.8 oe

5b(ii) · 2 marks

  • 2 marks

    w+6y5 oe final answer

5c · 2 marks

  • 2 marks

    (5−x)(3y+x) or −(x−5)(3y+x) final answer

5d · 4 marks

  • 4 marks

    x2−2x+9(x−3)(x+3) final answer or x2−2x+9x2−9 final answer

6a · 3 marks

  • 3 marks

    180 or 179.5 to 179.6…

6b · 2 marks

  • 2 marks

    20

6c · 5 marks

  • 5 marks

    653 or 653.1 to 653.2…

7a · 1 mark

  • 1 mark

    (–4, 1)

7b · 2 marks

  • 2 marks

    6.08 or 6.082 to 6.083

7c · 3 marks

  • 3 marks

    (4−8)

7d · 4 marks

  • 4 marks

    y=52x+11 oe final answer

8a · 3 marks

  • 3 marks

    1.97[0…]

8b · 5 marks

  • 5 marks

    195 or 194.79 to 194.81

9a · 4 marks

  • B2

    [x =] 98

  • B2

    [y =] 72

9b · 6 marks

  • 6 marks

    35.2 or 35.16 to 35.24

10a · 2 marks

  • M1

    r+r+6=x oe

  • A1

    r=x−62 leading to fraction red = x−62x

10b · 2 marks

  • M1

    green in A = x2+3 oe

  • A1

    Total in B = x+4(x2+3) oe leading to fraction red = x3x+12

10c · 3 marks

  • M1

    (x−6)(3x+12)=2x2 oe

  • M1

    3x2−18x+12x−72

  • A1

    Correct rearrangement to x2−6x−72=0

10d · 2 marks

  • B1

    (x+6)(x−12)[=0]

  • B1

    12, –6

10e · 1 mark

  • 1 mark

    9

11a · 2 marks

  • 2 marks

    49

11b · 2 marks

  • 2 marks

    256625 oe

11c · 3 marks

  • 3 marks

    42115 oe

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  3. 3
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  5. 5
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  6. 6
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  7. 7
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  8. 8
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  9. 9
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  10. 10
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  11. 11
    Question 117 marks
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