A Level Chemistry 9701 Paper 41, May/June 2023

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9701/41 · May/June 2023

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1
Figure 1 of 3 for question 1
Figure 2 of 3 for question 1
Figure 3 of 3 for question 1
a

Group 2 nitrates decompose when heated. Describe how the thermal stability of Group 2 nitrates changes with increasing proton number. Explain your answer.

[3]
b

Copper(II) nitrate decomposes in a similar manner to Group 2 nitrates. Write an equation for the decomposition of Cu(NO3)2.

[1]
c

Cu(NO3)2 is added to water to form solution A. Fig. 1.1 shows some reactions of solution A. Complete Table 1.1 to show the formula and colour of each of the copper-containing species present in A, B, C and D.

[4]
d(i)

EDTA4− is a polydentate ligand. Explain what is meant by a polydentate ligand.

[2]
d(ii)

Group 2 metal ions can form complexes similar to those of transition elements. A solution of EDTA4− is added to water containing [Ca(H2O)6]2+ to form a new complex, [CaEDTA]2−, as shown. equilibrium 1 [Ca(H2O)6]2++EDTA4−⇌[CaEDTA]2−+6H2O Circle on the structure of EDTA4− in Fig. 1.2 the six atoms that form bonds with the metal ion.

[1]
d(iii)

The calcium ions in [Ca(H2O)6]2+ and [CaEDTA]2− have a coordination number of 6. Explain what is meant by coordination number.

[1]
d(iv)

The complex [CaEDTA]2− can be used to remove toxic metals from the body. Table 1.2 shows the numerical values for the stability constants, Kstab, for some metal ions with EDTA4−. An aqueous solution containing [CaEDTA]2− is added to a solution containing equal concentrations of Cr3+(aq), Fe3+(aq) and Pb2+(aq). The resulting mixture is left to reach a state of equilibrium. State the type of reaction when [CaEDTA]2− reacts with Cr3+(aq), Fe3+(aq) and Pb2+(aq).

[1]
d(v)

Deduce the relative concentrations of [CrEDTA]−, [FeEDTA]− and [PbEDTA]2− present in the resulting mixture. Explain your answer. .......................................... > .......................................... > .......................................... highest concentration lowest concentration

[1]
e

The number of moles of water of crystallisation in a hydrated ionic salt can be determined by titration using aqueous EDTA4− ions with a suitable indicator. • 0.255 g of hydrated chromium(III) sulfate, Cr2(SO4)3⋅nH2O, is dissolved in water and made up to 100 cm3 in a volumetric flask. • 25.0 cm3 of this solution requires 26.2 cm3 of 0.00800 mol dm−3 aqueous EDTA4− ions to reach the end-point. The reaction occurs as shown. [Cr(H2O)6]3++EDTA4−→[CrEDTA]−+6H2O Use the data to calculate the value of n in the formula of Cr2(SO4)3⋅nH2O. Show your working.

[3]
f

A solution of Cr3+(aq) and a solution of Fe3+(aq) have different colours. Explain why the two complexes have different colours.

[2]
2
Figure 1 of 5 for question 2
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Figure 5 of 5 for question 2
a

Some transition element complexes can show stereoisomerism. State two types of stereoisomerism shown by transition element complexes. 1 ................................................................................................................................ 2 ................................................................................................................................

[1]
b

The complexes [Pt(NH3)2Cl2] and [Pt(en)2]2+ have the same geometry (shape) around the metal ion. [Pt(NH3)2Cl2] exists as two stereoisomers whereas [Pt(en)2]2+ only has one possible structure. State the geometry around the metal ion.

[1]
c

The complex [Cr(en)3]2+ exists as two stereoisomers whereas the complex [Cr(OCH2CH2NH2)3]− exists as four stereoisomers. Complete the three-dimensional diagrams in Fig. 2.1 to show the four stereoisomers of [Cr(OCH2CH2NH2)3]−. Represent the ligand −OCH2CH2NH2 by using O—N.

[3]
d(i)

The complex [Cr(OCH2CH2NH2)3]− is formed by reacting Cr2+(aq) with the conjugate base of 2-aminoethanol. A synthesis of 2-aminoethanol is shown in Fig. 2.2. Suggest the mechanism for step 1 of the reaction of oxirane with ammonia in Fig. 2.3. Include all relevant curly arrows, lone pairs of electrons, charges and partial charges. Draw the structure of the organic intermediate.

[3]
d(ii)

A small amount of by-product E, shown in Fig. 2.4, is produced during the reaction shown in Fig. 2.2. Suggest how the formation of by-product E can be minimised.

[1]
d(iii)

Compound F, C4H9NO, can be formed from the reaction of by-product E, C4H11NO2, with concentrated H2SO4. Compound F is a saturated and basic organic compound. Suggest a structure for compound F. State the type of reaction undergone by E to form F.

[2]
3
Figure 1 of 2 for question 3
Figure 2 of 2 for question 3
a(i)

Aqueous acidified iodate(V) ions, IO3−, react with iodide ions, as shown. IO3−+6H++5I−→3I2+3H2O The initial rate of this reaction is investigated. Table 3.1 shows the results obtained. The rate equation for this reaction is rate=k[IO3−][H+]2[I−]2. Explain what is meant by order of reaction.

[1]
a(ii)

Complete Table 3.2.

[1]
a(iii)

Use your answer to (a)(ii) to sketch lines in Fig. 3.1 to show the relationship between the initial rates and the concentrations of [IO3−] and [I−].

[1]
a(iv)

Use data from Table 3.1 to calculate the rate constant, k, for this reaction. Include the units of k.

[2]
a(v)

Use data from Table 3.1 to calculate the concentration of hydrogen ions, [H+], in experiment 2.

[1]
a(vi)

This reaction is repeated in two separate experiments. The experiments are carried out at the same temperature and with the same concentrations of I− and IO3−. One experiment takes place at pH 1.0 and the other experiment takes place at pH 2.0. Calculate the value of rate at pH 1.0rate at pH 2.0.

[1]
b

In aqueous solution, iron(III) ions react with iodide ions, as shown. 2Fe3++2I−→2Fe2++I2 The initial rate of reaction is first order with respect to Fe3+ and second order with respect to I−. The mechanism for this reaction has three steps. Each step involves only two ions reacting together. Suggest equations for the three steps of this mechanism. Identify the rate-determining step.

[3]
4
Figure 1 of 4 for question 4
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Figure 3 of 4 for question 4
Figure 4 of 4 for question 4
a

State the hybridisation of the carbon atoms and the C–C–H bond angle in benzene, C6H6. Explain how orbital overlap leads to the formation of σ and π bonds in benzene.

[3]
b(i)

Compound Z can be synthesised from benzene in three steps by the route shown in Fig. 4.1. Draw structures for X and Y in Fig. 4.1.

[2]
b(ii)

Give the reagents and conditions for steps 1, 2 and 3. step 1 ................................................................................................................................ step 2 ................................................................................................................................ step 3 ................................................................................................................................

[3]
c

Compound W is an isomer of Z. Give the systematic name of W.

[1]
d

Complete Table 4.1 to show the number of peaks observed in the carbon-13 NMR spectrum for W and Z.

[1]
5
a(i)

The exhaust systems of most modern gasoline-fuelled cars contain a catalytic converter with three metal catalysts. These metals act as heterogeneous catalysts. Name three metal catalysts used in catalytic converters.

[1]
a(ii)

Explain what is meant by a heterogeneous catalyst.

[1]
b(i)

The exhaust systems of many diesel-fuelled cars contain an additional system to reduce vehicle emissions. This uses a liquid that is added to the exhaust system. This liquid contains urea, (NH2)2CO, which decomposes on heating to isocyanic acid, HNCO, and ammonia. reaction 1 (NH2)2CO→HNCO+NH3 Isocyanic acid reacts with water vapour to form ammonia and carbon dioxide. reaction 2 HNCO(g)+H2O(g)→NH3(g)+CO2(g) Some values for standard enthalpy changes of formation, ΔHf⊖, and standard entropies, S⊖, are given in Table 5.1. Explain what is meant by the term entropy of a system.

[1]
b(ii)

Use the data in Table 5.1 to calculate ΔG⊖ for reaction 2 at 25 ∘C. Show your working.

[4]
c

The ammonia formed in reactions 1 and 2 can be used to remove nitrogen dioxide from exhaust emissions, as shown. reaction 3 8NH3+6NO2→7N2+12H2O Use the equations for reactions 1, 2 and 3 to construct an overall equation for the reduction of NO2 by (NH2)2CO.

[1]
d

Isocyanic acid, HNCO, can form cyanuric acid, C3H3N3O3, under certain conditions. C3H3N3O3 has a cyclic structure containing alternating carbon and nitrogen atoms in the ring system. Suggest a structure for cyanuric acid.

[1]
e(i)

Isocyanic acid, HNCO, is a weak acid. HNCO+H2O⇌H3O++NCO−pKa=3.70 at 25 ∘C Write the mathematical expressions for pKa and pH. pKa= ................................................................................................................................. pH= ...................................................................................................................................

[1]
e(ii)

Calculate the pH of 0.120 mol dm−3 HNCO(aq). Give your answer to three significant figures.

[2]
e(iii)

Calculate the percentage of HNCO molecules that are ionised in 0.120 mol dm−3 HNCO.

[1]
6
Figure 1 of 2 for question 6
Figure 2 of 2 for question 6
a(i)

Compound H has the structural formula CH2=CHCH(NH2)COOH. Name all the functional groups in H.

[2]
a(ii)

Compound H exhibits stereoisomerism. Draw three-dimensional structures for the two stereoisomers of H. Name this type of stereoisomerism.

[2]
b(i)

Compound H can be prepared from the reaction of J with an excess of hot aqueous acid. Complete Fig. 6.2 to show the equation for this reaction.

[1]
b(ii)

Name the type of reaction in (b)(i).

[1]
c(i)

Polymers consist of monomers joined together by undergoing either addition or condensation polymerisation. Compound H can react to form an addition polymer, K, or a condensation polymer, L, depending on the conditions. Draw one repeat unit of addition polymer K.

[1]
c(ii)

Draw two repeat units of condensation polymer L. The new functional group formed should be displayed.

[2]
c(iii)

Explain why condensation polymers can normally biodegrade more readily than addition polymers.

[1]
7
Figure 1 of 3 for question 7
Figure 2 of 3 for question 7
Figure 3 of 3 for question 7
a

State the relative basicities of ethanamide, diethylamine and ethylamine in aqueous solution. Explain your answer. ............................................. > ............................................. > ............................................. most basic least basic

[4]
b(i)

The amino acid alanine, H2NCH(CH3)COOH, can act as a buffer. Define a buffer solution.

[2]
b(ii)

Write two equations to show how an aqueous solution of alanine can act as a buffer solution.

[2]
c(i)

Glutamic acid is another amino acid that acts as a buffer. Draw the skeletal formula for glutamic acid.

[1]
c(ii)

Draw the structure for the dipeptide, ala-glu, formed from one molecule of alanine and one molecule of glutamic acid. The peptide bond formed should be displayed.

[2]
d

The isoelectric point of alanine is 6.0 and of glutamic acid is 3.2. A mixture of the dipeptide, ala-glu, and its two constituent amino acids, alanine and glutamic acid, is analysed by electrophoresis using a buffer at pH 6.0. Draw and label three spots on Fig. 7.2 to indicate the predicted position of each of these three species after electrophoresis. Explain your answer.

[3]
e(i)

Alanine, H2NCH(CH3)COOH, reacts with methanol to form the ester G under certain conditions. The proton (1H) NMR spectrum of G dissolved in D2O is shown in Fig. 7.3. Complete Table 7.2 for the proton (1H) NMR spectrum of G.

[3]
e(ii)

The proton (1H) NMR spectrum of G dissolved in CDCl3 is obtained. Describe the difference observed between this spectrum and the proton NMR spectrum in D2O shown in Fig 7.3. Explain your answer.

[1]
8
a

Complete Table 8.1 by placing one tick (✓) in each row to indicate the sign of each type of energy change under standard conditions.

[1]
b

Define enthalpy change of hydration.

[1]
c(i)

Table 8.2 shows various energy changes which can be used in the following questions. Select and use relevant data from Table 8.2 to calculate the lattice energy, ΔHlatt⊖, of CaBr2(s). It may be helpful to draw a labelled energy cycle. Show your working.

[3]
c(ii)

Select and use relevant data from Table 8.2 and your answer to (c)(i) to calculate the standard enthalpy change of hydration, ΔHhyd⊖, of Br−. It may be helpful to draw a labelled energy cycle. If you were not able to answer (c)(i), use −2500 kJ mol−1 as your value for ΔHlatt⊖ of CaBr2(s). This is not the correct value. Show your working.

[2]
c(iii)

The enthalpy change of hydration of the Br− ion is more negative than the enthalpy change of hydration of the I− ion. Explain why.

[2]

Mark scheme

9701/41 · May/June 2023

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1a · 3 marks

  • M1

    increases (down the group)

  • M2

    radius / size of (cat)ion / M2+ increases

  • M3

    less polarisation / distortion of anion / nitrate ion / NO3– OR less weakening of N–O / N=O (bond)

1b · 1 mark

  • 1 mark

    Cu(NO3)2 → CuO + 2NO2 + ½O2

1c · 4 marks

  • 4 marks
    copper-containing speciesformula of copper-containing species formedcolour copper-containing formed
    A[Cu(H2O)6]2+(pale) blue
    BCu(H2O)4(OH)2 or Cu(OH)2(pale) blue
    C[Cu(NH3)4(H2O)2]2+dark blue
    DCuCl42–yellow

1d(i) · 2 marks

  • M1

    (a species) that donates more than two lone pairs

  • M2

    to form dative / coordinate bonds to a metal atom or ion

1d(ii) · 1 mark

  • 1 mark

    six atoms circled, 2N and 4O from different CO2–

1d(iii) · 1 mark

  • 1 mark

    the number of co-ordinate bonds being formed by the metal ion

1d(iv) · 1 mark

  • 1 mark

    ligand exchange

1d(v) · 1 mark

  • 1 mark

    [FeEDTA]– > [CrEDTA]– > [PbEDTA]2– highest concn lowest concn AND Kstab of [FeEDTA]– is highest

1e · 3 marks

  • M1

    moles of Cr3+ = 2.096 × 10–4 in 25.0 cm3)

  • M2

    moles of Cr3+ = 8.384 × 10–4 (in 100.0 cm3) moles of Cr2(SO4)3•nH2O = 8.384 × 10–4 / 2 = 4.192 × 10–4

  • M3

    Mr of Cr2(SO4)3•nH2O = 0.2550 / 4.192 × 10–4 = 608.3 n = (608.3 – 392.3) / 18 = 12

1f · 2 marks

  • M1

    ΔE is different

  • M2

    different frequency (of light) is absorbed

2a · 1 mark

  • 1 mark

    geometrical / cis-trans AND optical

2b · 1 mark

  • 1 mark

    square planar

2c · 3 marks

  • 3 marks

    Structures 1, 2, 3, and 4

2d(i) · 3 marks

  • M1

    two correct curly arrows

  • M2

    correct dipole

  • M3

    correct structure of intermediate

2d(ii) · 1 mark

  • 1 mark

    use an excess of ammonia OR limiting amount of oxirane

2d(iii) · 2 marks

  • M1

    correct structure of morpholine

  • M2

    elimination / dehydration / condensation

3a(i) · 1 mark

  • 1 mark

    the power to which the concentration of a reactant is raised in the rate equation

3a(ii) · 1 mark

  • 1 mark

    the order of reaction with respect to [IO3–] = 1, [H+] = 2, [I–] = 2, overall = 5

3a(iii) · 1 mark

  • 1 mark

    Graphs showing straight line through origin for [IO3–(aq)] vs rate, and upward curve for [I–(aq)] vs rate

3a(iv) · 2 marks

  • M1

    k = rate / [I–]2[IO3–][H+]2 = (4.20 × 10-2)/(0.0252 × 0.04x0.0152) = 7.47 × 106

  • M2

    units = mol–4 dm12min–1

3a(v) · 1 mark

  • 1 mark

    0.0709 = k × 0.12 × [H+]2 × 0.01252 [H+] = 2.25 × 10-2

3a(vi) · 1 mark

  • 1 mark

    x = 102 / 1 = 100

3b · 3 marks

  • M1

    step 1 Fe3+ + I– → FeI2+

  • M2

    step 2 FeI2+ + I– → Fe2+ + I2– OR FeI2+ + I– → FeI2+ AND slowest step = step 2

  • M3

    step 3 Fe3+ + I2– → Fe2+ + I2 OR FeI2+ + Fe3+ → 2Fe2+ + I2

4a · 3 marks

  • M1

    bond angle = 120° AND carbons are sp2

  • M2

    σ bonds are formed by end-on-end / head on / head to head / linear overlap of orbitals

  • M3

    π bonds are formed by sideways / lateral overlap of p orbitals

4b(i) · 2 marks

  • 1 mark

    Structure of X

  • 1 mark

    Structure of Y

4b(ii) · 3 marks

  • M1

    step 1 (CH3)2CHBr and FeBr3 / Al Br3

  • M2

    step 2 conc HNO3 and conc H2SO4

  • M3

    step 3 Sn and conc HCl

4c · 1 mark

  • 1 mark

    3,4,5-trimethylphenylamine

4d · 1 mark

  • 1 mark

    W = 6, Z = 6

5a(i) · 1 mark

  • 1 mark

    palladium, platinum and rhodium / Pt, Pd, Rh

5a(ii) · 1 mark

  • 1 mark

    a catalyst in a different state / phase to the reactants / substrate

5b(i) · 1 mark

  • 1 mark

    measure / degree of disorder / randomness of a system OR the number of possible arrangements of the particles and the energy in a system

5b(ii) · 4 marks

  • M1

    ΔS° = (192.8) + 213.8 – 238.2 – 188.8 ΔS° = -20.4 (J K–1 mol–1)

  • M2

    ΔH° = (–45.9) + (–393.5) – (–101.7) – (–241.8) ΔH° = -95.9 (kJ mol–1)

  • M3

    ΔG° = ΔH° – TΔS°

  • M4

    ΔG° = –95.9 – (298 × –0.0204) = –89.8 (kJ mol–1)

5c · 1 mark

  • 1 mark

    4(NH2)2CO + 6NO2 → 7N2 + 8H2O + 4CO2

5d · 1 mark

  • 1 mark

    Structure of 1,3,5-triazinane-2,4,6-trione (isocyanuric acid)

5e(i) · 1 mark

  • 1 mark

    pKa = –log Ka AND pH = –log [H+]

5e(ii) · 2 marks

  • M1

    [H+] = √0.120 × 2.00 × 10–4 = 4.89(317) × 10–3

  • M2

    pH = 2.31

5e(iii) · 1 mark

  • 1 mark

    % ionisation = 4.89 × 10-3/0.12 × 100 = 4.1%

6a(i) · 2 marks

  • 2 marks

    carboxylic acid, amine, alkene

6a(ii) · 2 marks

  • 2 marks

    3D optical isomers of 2-aminobut-3-enoic acid and optical

6b(i) · 1 mark

  • 1 mark

    + 2H2O → 2-aminobut-3-enoic acid + glycolic acid (structures shown)

6b(ii) · 1 mark

  • 1 mark

    hydrolysis

6c(i) · 1 mark

  • 1 mark

    structure of repeat unit of polymer formed from 2-aminobut-3-enoic acid

6c(ii) · 2 marks

  • M1

    amide linkage displayed correctly

  • M2

    rest of the structure correct

6c(iii) · 1 mark

  • 1 mark

    condensation polymers can be hydrolysed

7a · 4 marks

  • M1

    diethylamine > ethylamine > ethanamide

  • M2

    basicity linked to ability of lone pair on N to accept a proton / H+

  • M3

    electron donating ethyl group increases electron density on N / makes lone pair more available for donation

  • M4

    lone pair of electrons on N is delocalised into C=O group

7b(i) · 2 marks

  • M1

    resists change in pH

  • M2

    when a small amount of acid or alkali is added

7b(ii) · 2 marks

  • M1

    H2NCH(CH3)COOH + H+ → H3N+CH(CH3)COOH

  • M2

    H2NCH(CH3)COOH + OH– → H2NCH(CH3)COO– + H2O

7c(i) · 1 mark

  • 1 mark

    Structure of glutamic acid

7c(ii) · 2 marks

  • M1

    displayed peptide bond (between two amino acids)

  • M2

    rest of the structure correct

7d · 3 marks

  • M1

    relative positions of the spots drawn

  • M2

    Ala is a zwitterion / neutral / at its isoelectric point (at pH 6) OR ala-glu AND glu are negatively charged

  • M3

    glu has lower Mr OR ala-glu has higher Mr

7e(i) · 3 marks

  • 3 marks
    chemical shift (δ)splitting patternnumber of 1H atoms responsible for the peaknumber of protons on the adjacent carbon(s)
    1.4doublet31
    3.5singlet30
    4.0quartet13

7e(ii) · 1 mark

  • 1 mark

    one extra peak for NH2 group seen in CDCl3, AND H exchanged for D in D2O

8a · 1 mark

  • 1 mark

    lattice energy: always negative; enthalpy of hydration: always negative; enthalpy of solution: either negative or positive

8b · 1 mark

  • 1 mark

    The energy / enthalpy change when 1 mole of gaseous ions is dissolved in water

8c(i) · 3 marks

  • M1

    use of correct six numbers only 682.8 178.2 590 1145 111.9 324.6

  • M2

    2× used correctly with Br (2 × 111.9 and 2 × 324.6)

  • M3

    correct signs and evaluation to give –2170.6 kJ mol–1

8c(ii) · 2 marks

  • M1

    use of correct three numbers only 2170.6 103.1 and 1579

  • M2

    correct signs & evaluation –347 kJ mol–1

8c(iii) · 2 marks

  • M1

    Br– has a smaller ionic radius

  • M2

    Br– has stronger attractive forces with water molecules

Questions

  1. 1
    Question 119 marks
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  2. 2
    Question 211 marks
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  3. 3
    Question 310 marks
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  4. 4
    Question 410 marks
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  5. 5
    Question 513 marks
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  6. 6
    Question 610 marks
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  7. 7
    Question 718 marks
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  8. 8
    Question 89 marks
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