IGCSE Mathematics 0580 Paper 43, May/June 2023

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0580/43 · May/June 2023

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1
a(i)

Tomas sells a computer, a bike and a phone. The amounts he receives are in the ratio computer : bike : phone = 14 : 17 : 9. Calculate the amount he receives for the phone as a percentage of the total.

[2]
a(ii)

The total amount he receives is $560. Calculate how much he receives for the bike.

[2]
a(iii)

Tomas originally bought the bike for $195. He wanted to make a profit of at least 25% when he sold it. Does Tomas make a profit of at least 25%? You must show all your working to support your decision.

[3]
b

Ulla invests $725 for 6 years in an account paying simple interest at a rate of 1.3% per year. Calculate the total interest earned at the end of 6 years.

[2]
c

In a sale, all prices are reduced by 24%. Victor pays $36.86 for a pair of shoes in the sale. Calculate the original price of the shoes.

[2]
2
a(i)

Anna records the number of text messages she receives for 14 days. 17 15 31 38 31 22 13 18 21 27 28 21 31 29 Complete the stem-and-leaf diagram. Key: ...........................................................

[3]
a(ii)

Find the median.

[1]
a(iii)

Find the mode.

[1]
a(iv)

Find the range.

[1]
b

In a shop, there are 4 red and 8 grey phones. Anna and Pete each pick one of these phones at random. Work out the probability that they both pick a grey phone.

[2]
3
a(i)

The scale drawing shows two sides, AB and BC, of a field. The scale is 5 centimetres represents 200 metres. Measure angle ABC.

[1]
a(ii)

X is a point on BC. BX=332 m. Mark the point X on the diagram.

[2]
a(iii)

Find the scale in the form 1:n.

[2]
b

A bronze statue is 4.5 m high and has a mass of 195 200 kg. The density of bronze is 8000 kg/m3. The volume of a mathematically similar model of the statue is 0.385 m3. Calculate the height of the model. [Density=Mass÷Volume]

[5]
4
Figure 1 of 3 for question 4
Figure 2 of 3 for question 4
Figure 3 of 3 for question 4
a

A, B and C are three towns and the bearing of C from A is 114∘. B is due south of A and AC=BC. Calculate the bearing of B from C.

[3]
b(i)

P, Q, R and S lie on a circle. MPN is a tangent to the circle at P. Angle MPS=58∘, angle PSR=74∘ and angle QPN=27∘. Find angle PRS.

[1]
b(ii)

Find angle PQR.

[1]
b(iii)

Find angle RPQ.

[2]
c

A, B and C lie on a circle, centre O, with diameter AC. TAM and TBN are tangents to the circle and angle ATO=34∘. Using values and geometrical reasons, complete these statements to show that CB is parallel to OT. In triangles AOT and BOT, OT is common. Angle OAT=angle OBT=90∘ because .................................................................................... ..................................................................................................................................................... AT=BT because ........................................................................................................................ ..................................................................................................................................................... Triangle AOT is congruent to triangle BOT because of congruence criterion ........................... Angle AOT=angle BOT=56∘ because angles in a triangle add up to 180∘. Angle BOC= ...................... ∘ because ...................................................................................... Angle OBC= ...................... ∘ because ...................................................................................... ..................................................................................................................................................... CB is parallel to OT because ......................................................................................................

[6]
5
Figure 1 of 2 for question 5
Figure 2 of 2 for question 5
a(i)

ABC is a scalene triangle on horizontal ground. AYX is a straight vertical post, held in place by two straight wires XB and YC. AC=4.8 m, BC=5.6 m and angle ACB=20.4∘. Calculate AB.

[3]
a(ii)

Angle XBA=64∘. Calculate AX.

[2]
a(iii)

AY=2.9 m. Calculate the area of triangle YAC.

[2]
b

In triangle PQR, M is the midpoint of PQ. RM=8 cm, angle PRM=30∘ and angle RMQ=75∘. Calculate PQ.

[5]
6
a(i)

The cumulative frequency table shows information about the speed of each of 200 cars as they pass a speed camera.

Speed (v km/h)v⩽70v⩽80v⩽90v⩽95v⩽100v⩽120
Cumulative frequency1246115155177200

On the grid, draw the cumulative frequency diagram.

[3]
a(ii)(a)

Use your cumulative frequency diagram to find an estimate of the median

[1]
a(ii)(b)

Use your cumulative frequency diagram to find an estimate of the interquartile range

[2]
a(ii)(c)

Use your cumulative frequency diagram to find an estimate of the number of cars with a speed greater than 110 km/h.

[2]
b(i)

The frequency table shows information about the mass of each of 50 trucks.

Mass (m kg)2000<m⩽26002600<m⩽35003500<m⩽50005000<m⩽5700
Frequency1215167

Calculate an estimate for the mean mass of the trucks.

[4]
b(ii)

In a histogram showing this information, the height of the first block is 6 cm. Calculate the heights of the remaining three blocks. Height of block for 2600<m⩽3500 .......................................... cm Height of block for 3500<m⩽5000 .......................................... cm Height of block for 5000<m⩽5700 ........................................... cm

[3]
7
Figure 1 of 1 for question 7
a

The diagram shows the graph of a function. Put a ring around the word which correctly identifies the type of function. reciprocal quadratic cubic exponential linear

[1]
b(i)

On the diagram, sketch the graph of y=12x,x≠0.

[2]
b(ii)

Solve the equation 12x=2x.

[2]
c(i)

On the diagram, sketch the graph of y=sin⁡x for 0∘⩽x⩽360∘.

[2]
c(ii)

Solve the equation 3sin⁡x+1=0 for 0∘⩽x⩽360∘.

[3]
8
a

A shop sells shirts for $x and jackets for $(x+27). The shop sells 4 shirts and 3 jackets for a total of $194.75. Write down and solve an equation to find the cost of one shirt.

[3]
b

Solve the simultaneous equations. You must show all your working. x2+4y=37 5x+y=−8

[5]
c

A solid cylinder has radius x and height 6x. A sphere of radius r has the same surface area as the total surface area of the cylinder. Show that r2=72x2. [The surface area, A, of a sphere with radius r is A=4πr2.]

[4]
9
Figure 1 of 2 for question 9
Figure 2 of 2 for question 9
a(i)

The diagram shows a shape made from a square ABCD and two equal sectors of a circle. The square has side 11 cm. MAB and DCN are straight lines. Calculate the area of the shape.

[3]
a(ii)

Calculate the perimeter of the shape.

[3]
b

The diagram shows a cube ABCDEFGH of edge 7 cm. Calculate the angle between AG and the base of the cube.

[4]
10

The table shows some values for y=2x−3.

x-2-100.511.522.5
y-2.75-1.58-0.1712.66
a

Complete the table.

[3]
b

On the grid, draw the graph of y=2x−3 for −2⩽x⩽2.5.

[4]
c

Use your graph to solve the equation 2x−3=2.

[1]
d

By drawing a suitable straight line, solve the equation 2x−x−1.5=0.

[4]
11

M has coordinates (4,1) and N has coordinates (−2,−7).

a

Find the length of MN.

[3]
b

Find the gradient of MN.

[2]
c

Find the equation of the perpendicular bisector of MN.

[4]
12

The equation of a curve is y=x4−8x2+5.

a

Find the derivative, (dydx), of y=x4−8x2+5.

[2]
b

Find the coordinates of the three turning points. You must show all your working.

[4]
c

Determine which one of these turning points is a maximum. Justify your answer.

[2]

Mark scheme

0580/43 · May/June 2023

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1a(i) · 2 marks

  • 2 marks

    22.5

1a(ii) · 2 marks

  • 2 marks

    238

1a(iii) · 3 marks

  • M2

    1.25 × 195 oe

  • A1

    243[.75] and No oe

1b · 2 marks

  • 2 marks

    56.55

1c · 2 marks

  • 2 marks

    48.5[0]

2a(i) · 3 marks

  • B2

    fully correct stem-and-leaf diagram

  • B1

    correct key

2a(ii) · 1 mark

  • 1 mark

    24.5

2a(iii) · 1 mark

  • 1 mark

    31

2a(iv) · 1 mark

  • 1 mark

    25

2b · 2 marks

  • 2 marks

    14/33 oe

3a(i) · 1 mark

  • 1 mark

    118

3a(ii) · 2 marks

  • 2 marks

    X is 8.3 cm from B

3a(iii) · 2 marks

  • 2 marks

    1 : 4000

3b · 5 marks

  • 5 marks

    1.13 or 1.128 to 1.129

4a · 3 marks

  • 3 marks

    246

4b(i) · 1 mark

  • 1 mark

    58

4b(ii) · 1 mark

  • 1 mark

    106

4b(iii) · 2 marks

  • 2 marks

    47

4c · 6 marks

  • 1 mark

    Radius perpendicular to tangent

  • 1 mark

    Tangents to circle from a/same point oe

  • 1 mark

    RHS

  • 1 mark

    68 angles on a [straight] line add up/sum to 180 oe

  • 1 mark

    56 [base angles of] isosceles triangle

  • 1 mark

    OBC = BOT Alternate angles

5a(i) · 3 marks

  • 3 marks

    2[.00] or 2.002 to 2.003 nfww

5a(ii) · 2 marks

  • 2 marks

    4.1[0] or 4.11 or 4.100 to 4.107 cao

5a(iii) · 2 marks

  • 2 marks

    6.96

5b · 5 marks

  • 5 marks

    11.3 or 11.31..

6a(i) · 3 marks

  • B1

    correct horizontal placement for 6 plots

  • B1

    correct vertical placement for 6 plots

  • B1

    dep on at least B1 for reasonable increasing curve through their 6 points

6a(ii)(a) · 1 mark

  • 1 mark

    87 to 89.5

6a(ii)(b) · 2 marks

  • 2 marks

    12.5 to 14

6a(ii)(c) · 2 marks

  • 2 marks

    Strict FT, 200 – their cumul freq reading from their graph at 110 given to nearest integer

6b(i) · 4 marks

  • 4 marks

    3576

6b(ii) · 3 marks

  • B1

    5

  • B1

    3.2

  • B1

    3

7a · 1 mark

  • 1 mark

    Cubic

7b(i) · 2 marks

  • 2 marks

    Correct sketch

7b(ii) · 2 marks

  • 2 marks

    ± 1/2 nfww

7c(i) · 2 marks

  • 2 marks

    Correct sketch through (0, 0) (180, 0) and (360, 0) with max and min at 1 and –1 resp.

7c(ii) · 3 marks

  • 3 marks

    199.5 or 199.47... and 340.5...

8a · 3 marks

  • M1

    4x + 3(x + 27) = 194.75 or 4x + 3x + 81 = 194.75

  • B2

    16.25 cao

8b · 5 marks

  • M2

    x² - 20x - 69[= 0] oe or y² + 116y - 861[= 0] oe

  • M1

    (x + 3)(x - 23) [= 0] oe or (y - 7)(y + 123) [= 0] oe

  • B2

    x = -3, y = 7; x = 23, y = -123 final answer

8c · 4 marks

  • M2

    2πx × 6x + 2πx² or 2πx(6x + x)

  • M1

    Their (2πx × 6x + 2πx²) = 4πr²

  • A1

    At least one further stage of working leading to r² = 7/2 x²

9a(i) · 3 marks

  • 3 marks

    311 or 311.0 to 311.1

9a(ii) · 3 marks

  • 3 marks

    78.6 or 78.55 to 78.56...

9b · 4 marks

  • 4 marks

    35.2 or 35.3 or 35.239… to 35.28

10a · 3 marks

  • B1

    -2.5

  • B1

    -2

  • B1

    -1

10b · 4 marks

  • 4 marks

    Correct curve

10c · 1 mark

  • 1 mark

    2.3 to 2.4

10d · 4 marks

  • M2

    ruled line y = x - 1.5

  • A2

    -1 and 1.55 to 1.7

11a · 3 marks

  • 3 marks

    10

11b · 2 marks

  • 2 marks

    4/3 or 8/6

11c · 4 marks

  • 4 marks

    y = -3/4 x - 9/4 or 4y + 3x + 9 = 0 oe final answers

12a · 2 marks

  • 2 marks

    4x³ - 16x cao

12b · 4 marks

  • B1

    Their dy/dx = 0 or stating dy/dx = 0

  • M1

    Correct method to solve their 4x³ - 16x = 0

  • A1

    [x =] 0, -2, 2

  • A1

    (0, 5) (-2, -11) (2, -11)

12c · 2 marks

  • 2 marks

    (0, 5) with correct reasoning

Questions

  1. 1
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  2. 2
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  3. 3
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  4. 4
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  5. 5
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  6. 6
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  7. 7
    Question 710 marks
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  8. 8
    Question 812 marks
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  9. 9
    Question 910 marks
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  10. 10
    Question 1012 marks
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  11. 11
    Question 119 marks
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  12. 12
    Question 128 marks
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