O Level Mathematics 4024 Paper 22, Oct/Nov 2023

Question paper and mark scheme100 marks11 questions

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Question paper

4024/22 · Oct/Nov 2023

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1
a(i)

Idris repairs computers. This is how he calculates the charge for a repair. $56 for the first hour Then $12.25 for each additional 15 minutes Work out the amount Idris charges for a repair that takes him 2 hours.

[2]
a(ii)

Idris charges $166.25 for another repair. He starts work on the repair at 2.30 pm. Find the time when he completes the repair.

[3]
b

Idris invests $6200 in an account paying compound interest at a rate of 1.7% per year. Calculate the total amount of interest earned at the end of 4 years.

[3]
c

The exchange rate between dollars ($) and euros (€) is $1 = €0.84 . Idris buys some equipment from a website that charges in euros. The equipment costs €760. Idris must pay 2.5% tax on this cost. Work out the amount Idris pays for the equipment including tax. Give your answer in dollars.

[3]
2
Figure 1 of 2 for question 2
Figure 2 of 2 for question 2
a(i)

Find the size of one interior angle of a regular 15-sided polygon.

[2]
a(ii)

The diagram shows part of a regular 15-sided polygon. Find the value of x.

[2]
b

A, B, C and D are points on the circle, centre O. AB is a diameter of the circle. Angle BAC=24∘. Find angle ADC. Give a reason for each step of your working.

[4]
3
Figure 1 of 1 for question 3
a(i)

Laila asks a group of people what type of exercise they prefer. The results are shown in the pie chart. 90 people prefer running. Calculate the total number of people Laila asks.

[2]
a(ii)

Work out the fraction of the group who prefer yoga. Write your answer in its simplest form.

[2]
b(i)

Laila records the number of steps she walks each day for 60 days. The table shows the results.

Number of steps (n thousand)5<n⩽88<n⩽1010<n⩽1212<n⩽1515<n⩽20
Frequency91614156

Complete the histogram to represent the data.

[3]
b(ii)

Laila has a target of 11 000 steps every day. Find an estimate for the percentage of these 60 days that Laila met her target.

[2]
4
a

Solve. 5x+6=3x

[2]
b

The mass of a plum is n grams. The mass of an apple is twice the mass of the plum. The mass of a banana is 50 grams more than the mass of the apple. The total mass of the plum, the apple and the banana is 450 grams. Form an equation in n and solve it to find the mass of the plum.

[3]
c

Solve by factorisation. x2−4x−21=0

[3]
5
a(i)

A bag contains 40 balls. 28 of the balls are red and the rest are green. Aisha takes a ball from the bag at random, notes its colour and replaces it. Find the probability that this ball is green.

[1]
a(ii)

Aisha repeats this 200 times. Work out the number of times she expects to take a green ball.

[1]
b(i)

A bag contains 9 blue balls and 7 yellow balls. Sergio takes two balls from the bag at random without replacement. Complete the tree diagram.

[2]
b(ii)

Find the probability that the two balls are the same colour.

[2]
6
Figure 1 of 1 for question 6
a(i)

Complete the table for y=4x10.

x00.511.522.53
y0.20.40.81.63.26.4
[1]
a(ii)

Draw the graph of y=4x10 for 0⩽x⩽3.

[3]
a(iii)

Use your graph to solve the equation 4x10=5.

[1]
a(iv)

By drawing a tangent, estimate the gradient of y=4x10 when x=2.

[2]
b

This is a sketch of the graph of y=x2+ax+b. Find the value of a and the value of b.

[3]
7
Figure 1 of 1 for question 7
a(i)

Point A and point B are shown on a centimetre square grid. ABC is a triangle. Here are five possible coordinates for point C. (−2,4)(−2,−1)(−1,−2)(6,1)(−4,6) Tick (✓) the two coordinates from the list that make ABC an isosceles triangle.

[2]
a(ii)

Find the column vector AB⃗.

[1]
a(iii)

A is the midpoint of the line DB. Find ∣DB⃗∣.

[3]
b

The equation of line P is y=4x−3. Line L is perpendicular to line P. Line L passes through the point (6,4). Find the coordinates of the point where line L crosses the x-axis.

[4]
8

The diagram shows a small rectangle inside a large rectangle. The height of the large rectangle is x cm. The length of the large rectangle is 4 times its height. The width of the shaded border is 3 cm. The area of the small rectangle is 80 cm2.

Figure 1 of 1 for question 8
a

Form an equation in x and show that it simplifies to 2x2−15x−22=0.

[4]
b

Solve the equation 2x2−15x−22=0. Show your working and give your answers correct to 2 decimal places.

[3]
c

Calculate the shaded area.

[2]
9
Figure 1 of 1 for question 9
a(i)

ABCD is a rectangular field. C is due south of A. AB=450 m and BC=210 m. Martha walks at an average speed of 5.2 km/h. Calculate the time Martha takes to walk once around the perimeter of the field. Give your answer correct to the nearest minute.

[3]
a(ii)

Show that the bearing of D from A is 245∘, correct to 3 significant figures.

[3]
b

PQR is a triangle and S is a point on PR. PS=10.3 cm, QR=12.6 cm, QP^S=42∘ and QR^S=35∘. Calculate QS.

[5]
10
Figure 1 of 1 for question 10
a(i)

[Volume of a cone =13πr2h] [Curved surface area of a cone =πrl] A solid is formed from a large cone with a small cone removed from the centre. The small cone is mathematically similar to the large cone. The vertex of the large cone is vertically below the vertex of the small cone. The height of the large cone is 21 cm and the diameter of the top is 18 cm. The height of the small cone is 14 cm. Show that the volume of the solid is 399π cm3.

[3]
a(ii)

Calculate the total surface area of the solid.

[6]
b

The height of a cylinder is 13 cm, correct to the nearest centimetre. The radius of the base of the cylinder is 4.5 cm, correct to the nearest 0.1 centimetre. Calculate the upper bound of the volume, in cm3, of the cylinder.

[3]
11

f(x)=4x+1g(x)=2x−3

a

Find f(−3).

[1]
b

Find g−1(x).

[2]
c

Simplify 2f(x)+1g(x). Give your answer as a single fraction, in terms of x, in its simplest form.

[3]

Mark scheme

4024/22 · Oct/Nov 2023

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1a(i) · 2 marks

  • 2 marks

    105[.00]

1a(ii) · 3 marks

  • 3 marks

    5.45 [pm] or 17 45

1b · 3 marks

  • 3 marks

    432.47

1c · 3 marks

  • 3 marks

    927.38 cao

2a(i) · 2 marks

  • 2 marks

    156

2a(ii) · 2 marks

  • 2 marks

    144

2b · 4 marks

  • 4 marks

    ∠ADC=114 with complete reasons

3a(i) · 2 marks

  • 2 marks

    240

3a(ii) · 2 marks

  • 2 marks

    524 cao

3b(i) · 3 marks

  • 3 marks

    Correct histogram

3b(ii) · 2 marks

  • 2 marks

    46.7 or 46.66 to 46.67 or 4623

4a · 2 marks

  • 2 marks

    –3

4b · 3 marks

  • B1

    n+2n+2n+50=450 oe

  • B2

    80

4c · 3 marks

  • B2

    (x+3)(x−7)[=0]

  • B1

    –3 7

5a(i) · 1 mark

  • 1 mark

    1240 oe

5a(ii) · 1 mark

  • 1 mark

    60

5b(i) · 2 marks

  • 2 marks

    Correct tree diagram 716 on first branch 715, 915 oe , 615 oe on second branches

5b(ii) · 2 marks

  • 2 marks

    1940 oe

6a(i) · 1 mark

  • 1 mark

    0.1 oe

6a(ii) · 3 marks

  • 3 marks

    Correct smooth curve

6a(iii) · 1 mark

  • 1 mark

    Reading their graph at y=5

6a(iv) · 2 marks

  • B1

    Tangent drawn at (2, 1.6)

  • B1

    1.7 to 2.5

6b · 3 marks

  • 3 marks

    [$a = $] –7 [$b = $] 10

7a(i) · 2 marks

  • 2 marks

    (–2, 4) (–2, –1) (–1, –2) (6, 1) (–4, 6) ✓ ✓

7a(ii) · 1 mark

  • 1 mark

    (53)

7a(iii) · 3 marks

  • 3 marks

    11.7 or 11.66…

7b · 4 marks

  • 4 marks

    (22,0)

8a · 4 marks

  • M2

    (x−6)(4x−6)=80 oe or 4x×x−80=3x+3x+4x×3+4x×3−4×3×3 oe

  • M1

    4x2−24x−6x+36[=80] or 4x2−80−3x−3x−12x−12x=−36 oe

  • A1

    Correct simplification to 2x2−15x−22=0

8b · 3 marks

  • B2

    −(−15)±(−15)2−4×2×−222×2 oe or −(−15)2×2±(−152×2)2−(−222)

  • B1

    –1.26 and 8.76

8c · 2 marks

  • 2 marks

    227 or 226.6 to 226.9…

9a(i) · 3 marks

  • 3 marks

    15 cao

9a(ii) · 3 marks

  • M2

    180+tan⁡−1(450210) oe or 270−tan⁡−1(210450) oe

  • A1

    244.98…

9b · 5 marks

  • 5 marks

    7.58 or 7.575 to 7.577

10a(i) · 3 marks

  • M1

    18×1421 or 1821=x14 oe leading to x=12 or 9×1421 or 921=y14 oe leading to y=6 or (1421)3 oe

  • A2

    13π×92×21−13π×62×14=399π or (1−(23)3)(13π×92×21)=399π

10a(ii) · 6 marks

  • 6 marks

    1070 or 1074 to 1075

10b · 3 marks

  • 3 marks

    878 or 878.0 to 878.1… nfww

11a · 1 mark

  • 1 mark

    –11

11b · 2 marks

  • 2 marks

    x+32 oe final answer

11c · 3 marks

  • 3 marks

    8x−5(4x+1)(2x−3) or 8x−58x2−10x−3 final answer

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  1. 1
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  2. 2
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  3. 3
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  4. 4
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  5. 5
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  6. 6
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  7. 7
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  8. 8
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  9. 9
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  10. 10
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  11. 11
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