O Level Mathematics 4024 Paper 22, May/June 2024

Question paper and mark scheme100 marks11 questions

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Question paper

4024/22 · May/June 2024

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1
a

Oranges cost $1.45 per kilogram. Asher buys 1.2 kg of oranges. Find the change he receives from $10.

[1]
b(i)

Maria pays a fee to sell strawberries at a market. Each day she pays $75 plus a payment for the mass of strawberries she sells. The fee Maria pays per day is shown on the graph. One day Maria’s fee is $240. Use the graph to find the mass of strawberries she sells that day.

[1]
b(ii)

On Saturday Maria sells 270 kg of strawberries. On Sunday she sells 220 kg of strawberries. Find the total fee she pays for these two days.

[2]
b(iii)

The fee per day for Maria now increases. Each day she now pays $90 plus a payment of $60 for every 100 kg of strawberries she sells. On the grid, draw a line to represent this new fee when she sells 0 kg to 500 kg of strawberries in a day.

[2]
c

Write the ratio 1.6 kg : 600 g : 2.4 kg in its simplest form.

[2]
2

The diagram shows a fair spinner numbered from 1 to 5. The score is the number the spinner lands on.

Figure 1 of 2 for question 2
Figure 2 of 2 for question 2
a(i)

The spinner is spun once. Find the probability that the score is 3

[1]
a(ii)

The spinner is spun once. Find the probability that the score is even.

[1]
b(i)

The spinner is spun twice. The two scores are added together. Complete the possibility diagram to show all the outcomes.

[2]
b(ii)

Find the probability that the outcome is 4.

[1]
b(iii)

Find the probability that the outcome is greater than 6.

[2]
3
a

The exchange rate between dollars ($) and Malaysian Ringgits (MYR) is 1=4.19MYR. The exchange rate between dollars ($) and Pakistani Rupees (PKR) is 1=179.12PKR. Find the exchange rate between Malaysian Ringgits and Pakistani Rupees.

[2]
b

Farhad invests $1500 in an account paying compound interest at a rate of 4% per year. Gulsan invests $1500 in an account paying simple interest at a rate of x% per year. Farhad and Gulsan have the same amount of money in their accounts at the end of 2 years. Calculate the value of x.

[4]
4
Figure 1 of 2 for question 4
Figure 2 of 2 for question 4
a(i)

The diagrams show the first four patterns in a sequence. Draw Pattern 5 on the grid below.

[1]
a(ii)

Complete the table.

[2]
a(iii)

Write an expression, in terms of n, for the total number of triangles in Pattern n.

[1]
a(iv)

Write an expression, in terms of n, for the number of white triangles in Pattern n.

[2]
b(i)

The 3rd term of a linear sequence is 34. The 8th term of the same linear sequence is 14. Find the value of the first term of this sequence.

[2]
b(ii)

Find the value of the first negative term of this sequence.

[1]
5
Figure 1 of 2 for question 5
Figure 2 of 2 for question 5
a

Describe fully the single transformation that maps shape A onto shape B.

[2]
b(i)

Shape A is mapped onto shape C by an enlargement of scale factor 3. Two of the vertices of shape C are (2,5) and (5,2). Find the coordinates of the centre of the enlargement.

[2]
b(ii)

Find the area of shape C.

[2]
c(i)

Transformation T is represented by the matrix (0−110). Transformation T maps shape A onto shape D. On the grid, draw shape D.

[2]
c(ii)

Describe fully the single transformation represented by the matrix (0−110).

[3]
6
Figure 1 of 3 for question 6
Figure 2 of 3 for question 6
Figure 3 of 3 for question 6
a

In the Venn diagram, shade the region represented by P∪Q.

[1]
b

Use set notation to describe the shaded region in the Venn diagram.

[1]
c(i)

E={1,2,3,4,5,6,7,8,9,10} A={x:x is a factor of 40} B={x:x is an odd number} Complete the Venn diagram.

[2]
c(ii)

List the elements of A′∩B.

[1]
c(iii)

One element of E is chosen at random. Find the probability that this element is in A∩B.

[1]
7
a

Solve x3=7.

[1]
b

Solve 6x−5=2(x+3).

[2]
c

Factorise 3x2−2x−8.

[2]
d

(ax+b)2=4x2−12x+c Given that a>0, find the value of each of a, b and c.

[3]
8

[Volume of a cone =13πr2h] [Volume of a sphere =43πr3] [Curved surface area of cone =πrl] [Surface area of a sphere =4πr2]

Figure 1 of 2 for question 8
Figure 2 of 2 for question 8
a(i)

A solid is formed by placing a cone on top of a hemisphere. The cone and the hemisphere each have radius r cm. The height of the solid is 10 cm. The curved surface area of the hemisphere is 145 cm2. Show that r=4.80, correct to 2 decimal places.

[3]
a(ii)

Calculate the volume of the solid.

[4]
a(iii)

Calculate the curved surface area of the cone.

[4]
b

The diagram shows two sectors of circles. Sector A has angle x and radius y. The angle of sector B is 20% smaller than the angle of sector A. The radius of sector B is 20% longer than the radius of sector A. Calculate the area of sector B as a percentage of the area of sector A.

[4]
9

A shop sells two varieties of apple tree.

Figure 1 of 1 for question 9
a(i)(a)

The cumulative frequency diagram shows the heights, in metres, of 80 Variety A trees. Use the diagram to estimate the median

[1]
a(i)(b)

the 30th percentile.

[2]
a(ii)

Trees with a height greater than y m are graded Class I. 25 of the 80 trees are graded Class I. Find the value of y.

[2]
a(iii)

Complete the frequency table for the heights of the Variety A trees.

[2]
b

The frequency table shows the heights of 50 Variety B trees. Using the midpoints of the intervals, the estimated mean height of these Variety B trees is 1.81 m. Calculate the value of p and the value of q.

[6]
10

The diagram shows a pentagon.

Figure 1 of 1 for question 10
a

Calculate the interior angle B.

[2]
b

In the pentagon, AE=8 cm and AD=15 cm. Calculate the length ED. Show your working and give your answer correct to 1 decimal place.

[5]
11

Q is the point (n,−4), R is the point (−1,8) and S is the point (3,2).

a

The length QR is 13 units. Find the two possible values of n.

[3]
b

RST is a straight line and RS:RT=2:5. Find the coordinates of T.

[2]
c

Find the equation of the perpendicular bisector of RS.

[5]

Mark scheme

4024/22 · May/June 2024

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1a · 1 mark

  • 1 mark

    8.26 cao

1b(i) · 1 mark

  • 1 mark

    328 to 332

1b(ii) · 2 marks

  • 2 marks

    388 to 402

1b(iii) · 2 marks

  • 2 marks

    Ruled line from (0, 90) to (500, 390)

1c · 2 marks

  • 2 marks

    8 : 3 : 12 cao

2a(i) · 1 mark

  • 1 mark

    15 oe

2a(ii) · 1 mark

  • 1 mark

    25 oe

2b(i) · 2 marks

  • 2 marks

    ........ 7 8 5 6 7 8 9 6 7 8 9 10

2b(ii) · 1 mark

  • 1 mark

    325 oe

2b(iii) · 2 marks

  • 2 marks

    1025 oe

3a · 2 marks

  • 2 marks

    42.75

3b · 4 marks

  • 4 marks

    4.08

4a(i) · 1 mark

  • 1 mark

    Pattern diagram

4a(ii) · 2 marks

  • 2 marks

    25 36 6 10 15 10 15 21

4a(iii) · 1 mark

  • 1 mark

    n2 oe final answer

4a(iv) · 2 marks

  • 2 marks

    12n2+12n oe final answer

4b(i) · 2 marks

  • 2 marks

    42

4b(ii) · 1 mark

  • 1 mark

    –2

5a · 2 marks

  • B1

    Reflection

  • B1

    y=−x oe

5b(i) · 2 marks

  • 2 marks

    (–4, 5)

5b(ii) · 2 marks

  • 2 marks

    13.5 or 1312

5c(i) · 2 marks

  • 2 marks

    Shape D at (–6, –1) (–4, –1) (–5, –2) (–6, –2)

5c(ii) · 3 marks

  • B1

    Rotation

  • B1

    90∘ anticlockwise oe

  • B1

    (0, 0) oe

6a · 1 mark

  • 1 mark

    Shaded intersection of sets P and Q

6b · 1 mark

  • 1 mark

    (X∩Y)′ oe

6c(i) · 2 marks

  • 2 marks

    Venn diagram with elements placed: A only: 2, 4, 8, 10; B only: 3, 7, 9; A ∩ B: 1, 5; outside: 6

6c(ii) · 1 mark

  • 1 mark

    3 7 9

6c(iii) · 1 mark

  • 1 mark

    210 oe

7a · 1 mark

  • 1 mark

    21

7b · 2 marks

  • 2 marks

    234 oe

7c · 2 marks

  • 2 marks

    (3x+4)(x−2) oe factorised final answer

7d · 3 marks

  • B1

    a=2

  • 1 mark

    b=−122×their a, their a≠0

  • 1 mark

    c=(their b)2, their b≠0

8a(i) · 3 marks

  • M1

    2×π×r2=145 or 4×π×r2=290

  • M1

    r2=1452π or 23.1 or 23.06 to 23.09 or r=1452π

  • B1

    r=4.803 to 4.804

8a(ii) · 4 marks

  • 4 marks

    357 to 358

8a(iii) · 4 marks

  • 4 marks

    107 or 106.7 to 106.8...

8b · 4 marks

  • 4 marks

    115.2

9a(i)(a) · 1 mark

  • 1 mark

    1.33 to 1.335

9a(i)(b) · 2 marks

  • 2 marks

    1.28 to 1.285

9a(ii) · 2 marks

  • 2 marks

    1.355 to 1.36

9a(iii) · 2 marks

  • 2 marks

    28 18 4

9b · 6 marks

  • 6 marks

    p=10 q=8

10a · 2 marks

  • 2 marks

    87

10b · 5 marks

  • M2

    x2+8x−161[=0] or sin⁡ADE=8sin⁡12015 oe

  • M2

    −8±82−4×1×−1612×1 oe or −82×1±(82×1)2−−1611 oe or 15sin⁡(60−their 27.5)sin⁡120 oe or 8sin⁡(60−their 27.5)sin⁡their 27.5 oe or 82+152−2×8×15cos⁡(θ) where θ=60−their 27.5

  • B1

    9.3 nfww

11a · 3 marks

  • 3 marks

    4, –6 nfww

11b · 2 marks

  • 2 marks

    (9, –7)

11c · 5 marks

  • 5 marks

    y=23x+413 oe simplified equation

Questions

  1. 1
    Question 18 marks
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  2. 2
    Question 27 marks
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  3. 3
    Question 36 marks
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  4. 4
    Question 49 marks
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  5. 5
    Question 511 marks
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  6. 6
    Question 66 marks
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  7. 7
    Question 78 marks
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  8. 8
    Question 815 marks
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  9. 9
    Question 913 marks
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  10. 10
    Question 107 marks
    Mark scheme ›
  11. 11
    Question 1110 marks
    Mark scheme ›

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